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Calculus Made Easy/Answers to Exercises

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ANSWERS.

Exercises I. (p. 25.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) .

(9) .

(10) .


Exercises II. (p. 33.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) , , and candle power per volt respectively.

(9) .
.

(10) .

(11) , , , , , .

(12) .


Exercises III. (p. 46.)

(1) (a) .

(b) .
(c) .
(d) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) .

(9) .

(10) .

(11) .

(12) , , or .

(13) , , , .

(14) , .


Exercises IV. (p. 51.)

(1) ; .

(2) ;

(3) .

(4) (Exercises III.):

(1) (a)

(b) , .
(c) .
(d) .

(2) , .

(3) , .

(4) .
.

(5) , .

(6) , .

(7) , .

(Examples, p. 41):

(1) , .

(2) , .

(3) , .

(4) .
.

(5) , .

(6) , .

(7)


Exercises V. (p. 64.)

(2) ; ; and feet per second.

(3) ; .

(4) feet per second.

(5) feet per second per second. Yes.

(6) Angular velocity radians per second; angular acceleration radians per second per second.

(7) . . , .

(8) , .

(9) , , and .

(10) , .


Exercises VI. (p. 73.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) .

(9) .


Exercises VII. (p. 75.)

(1) .

(2) .

(3) .


Exercises VIII. (p. 91.)

(2) .

(4) ; and the numerical values are: , , , and .

(5) .

(6) . Slope is zero where ; and is where .

(7) , .

(8) Intersections at , . Angles , .

(9) Intersections at , . Angles .

(10) , , .


Exercises IX. (p. 109.)

(1) Min.: , ; max.: , .

(2) .

(4) square inches.

(5) ; ; .

(6) Max. for ; min. for .

(7) Join the middle points of the four sides.

(8) , , no max.

(9) , , .

(10) At the rate of square feet per second.

(11) .

(12) .


Exercises X. (p. 118.)

(1) Max.: , ; min.: , .

(2) ; ; (a maximum).

(3) (a) One maximum and two minima. (b) One maximum. (; other points unreal.)

(4) Min.: , .

(5) Max: , .

(6) Max.: , . Min.: , .

(7) Max.: , . Min.: , .

(8) , .

(9) .

(10) Speed nautical miles per hour. Time taken hours. Minimum cost £. .

(11) Max. and min. for , . (See example no. 10, here.)

(12) Min.: , ; max.: , .


Exercises XI. (p. 130.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) .

(9) .

(10) .

(11) .

(12) .

(13) .

(14) .

(15) .

(16) .

(17) .

(18) .


Exercises XII. (p. 153.)

(1) .

(2) .

(3) .

(5) .

(6) .

(7) .

(8) .

(9) .

(10) .

(11) .

(12) .

(14) Min.: for .

(15) .

(16) .


Exercises XIII. (p. 162.)

(1) Let (∴ ), and use the Table on page 159.

(2) ; minutes.

(3) Take ; and use the Table on page 159.

(5) (a) ; (b) ; (c) .

(6) second.

(7) (a) ; (b) .

(8) , .

(9) is of , kilometres.

(10) , , mean ; , , .

(11) Min. for .

(12) Max. for .

(13) Min. for .


Exercises XIV. (p. 173.)

(1) (i) ;

(ii) and ;
(iii) and .

(2) or radians.

(3) .

(4) .

(5) .

(6) .

(7) The slop is , which is a maximum when or ; the value of the slope being then . When the slope is .

(8)

.

(9) .

(10) ; .

(11) (i) ;

(ii) ;
(iii) .

(12) (i) ;

(ii) ;
(iii) ;
(iv) ;
(v) .

(13) .

(14) .

(15) ; is max. for , min. for .


Exercises XV. (p. 180.)

(1) ; .

(2) ;

;
.

(3) ; .

(4) .

(5) ,

,
.

(7) Minimum for .

(8) (a) Length feet, width = depth = foot, vol. = cubic feet.

(b) Radius = feet = in., length = feet, vol. = .

(9) All three parts equal; the product is maximum.

(10) Minimum for .

(11) Min.: and .

(12) Angle at apex ; equal sides = length =.


Exercises XVI. (p. 190.)

(1) .

(2) .

(3) .

(4) (a) ;

(b) .

(5) .


Exercises XVII. (p. 205.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) by division. Therefore the answer is . (See pages 199 and 201.)

(9) .

(10) .

(11) .

(12) .

(13) .

(14) .

(15) .

(16) .

(17) .

(18) .


Exercises XVIII. (p. 224.)

(1) Area ; mean ordinate .

(2) Area of .

(3) Area ; mean ordinate .

(4) Area ; mean ordinate .

(5) , .

(6) Volume .

(7) .

(8) .

(9) Volume ; area of surface (from to ).

(10) , .

(12) Arithmetical mean ; quadratic mean .

(13) Quadratic mean ; arithmetical mean . The first involves a somewhat difficult integral, and may be stated thus: By definition the quadratic mean will be

.

Now the integration indicated by

is more readily obtained if for we write

.

For we write ; and, for ,

.

Making these substitutions, and integrating, we get (see p. 202)

.

At the lower limit the substitution of for causes all this to vanish, whilst at the upper limit the substitution of for gives . And hence the answer follows.

(14) Area is square units. Mean ordinate is .

(16) . (This solid is pear shaped.)


Exercises XIX. (p. 233.)

(1) .

(2) .

(3) .

(4) .

(5) .

(6) .

(7) .

(8) .

(9) .

(10) .

(11) .

(12) .

(13) .

(14) . (Let ; then, in the result, let .)

You had better differentiate now the answer and work back to the given expression as a check.

Every earnest student is exhorted to manufacture more examples for himself at every stage, so as to test his powers. When integrating he can always test his answer by differentiating it, to see whether he gets back the expression from which he started.

There are lots of books which give examples for practice. It will suffice here to name two: R. G. Blaine’s The Calculus and its Applications, and F. M. Saxelby’s A Course in Practical Mathematics.