In order to prove (ii) we may suppose, as usual, that
.
If , take . Then
.
If , take . Then
,
where
.
In either case the proof may be completed as before. Thus the only numbers which cannot be expressed in the form (5Β·2), in this case, are those of the form not exceeding . In other words, there is no exception when ; is the only exception when ; and are the only exceptions when ; , and are the only exceptions when .
(6Β·6)β.
By arguments similar to those used in (6Β·5), we can show that
(i) if , there is an infinity of integers which cannot be expressed in the form (5Β·2);
(ii) if is equal to , , , or , there is only a finite number of exceptions, namely the numbers of the form not exceeding .
(6Β·7)β.
By arguments similar to those used in (6Β·3), we can show that the only numbers which cannot be expressed in the form (5Β·2) are those of the form not exceeding , and those of the form lying between and .
(6Β·8)β.
By arguments similar to those used in (6Β·4), we can show that the only numbers which cannot be expressed in the form (5Β·2) are those of the form less than , and those of the form
,
lying between and , where if is of the form and if is of the form .
We have thus completed the discussion of the form (5Β·2), and determined the exceptional values of precisely whenever they are in finite number.