( 98 )
If he leaves three sons, and bequeaths to some onę as much as the share of one of his sons, less the share of a daughter, supposing he had one, plus one-third of the remainder of the one-third; the computation will be this:[1] distribute the heritage into such a number of parts as may be divided among the actual heirs, and also among them if a daughter were added to them. Such a number is twenty-one. Were a daughter among the heirs, her share would be three, and that of a son seven. The testator has therefore bequeathed to, the (73) legatee four-sevenths of the share of a son, and one-third of what remains from one-third. Take therefore one-third, and remove from it four-sevenths of the share of a son. There remains one-third of the capital less four-sevenths of the share of a son. Subtract now one-third of what remains of the one-third, that is to say, one-ninth of the capital less one-seventh and one-third of the seventh of the share of a son; the remainder
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Since there are 3 sons, each son’s share of the residue=. Were there 3 sons and a daughter, the daughter’s share
would be .
Let be the stranger’s legacy, and a son’s share
Then
but
and
a son’s share
the stranger’s legacy.