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CHAPTER I— EGYPTIAN ARITHMETIC
[2÷97
2 dived by 97
1⁄36 of 97 is 11⁄21⁄81⁄141⁄28,1⁄679 of 97 is 1⁄7, 1⁄776 of 97 is 1⁄8
| 1 | 97 | ||
| Find \ | 11⁄36 | 11⁄21⁄81⁄141⁄28 | |
| \ | 7 | 679 | 1⁄7 |
| \ | 8 | 776 | 1⁄8 |
2 divded by 99
1⁄66 of 99 is 11⁄2,1⁄198 of 99 is 1⁄2
| 1 | 99 | ||
| Find \ | 2⁄3 | 66 | 11⁄2 |
| \ | 2 | 198 | 1⁄2. |
2 divded by 101
Get 2 by operating on 101. 1⁄101 of 101 is 1. 1⁄102 of 101 is 1⁄2, 1⁄303 of 101 is 1⁄3, 1⁄606 of 101 is 1⁄6.
Working out:
| \ | 1 | 101 | 1 |
| \ | 2 | 202 | 1⁄2 |
| \ | 3 | 303 | 1⁄3 |
| \ | 6 | 606 | 1⁄6 |
SECTION II
Problems 1–6. Table of the Division of the Numbers 1–9 by 10
| Table | 1 | divided | by | 10 | gives | 1⁄10 |
| 2 | " | " | " | " | 1⁄5 | |
| 3 | " | " | " | " | 1⁄51⁄10 | |
| 4 | " | " | " | " | 1⁄31⁄15 | |
| 5 | " | " | " | " | 1⁄2 | |
| 6 | " | " | " | " | 1⁄21⁄10 | |
| 7 | " | " | " | " | 2⁄31⁄30 | |
| 8 | " | " | " | " | 2⁄31⁄101⁄30 | |
| 9 | " | " | " | " | 2⁄31⁄51⁄30 |
