21]
SECTION IV—PROBLEMS IN COMPLETION
65
Problem 17
Multiply 1⁄8 by 12⁄31⁄3.
| 1 | 1⁄3 | |
| 2⁄3 | 1⁄61⁄18 | |
| 1⁄3 | 1⁄9 | |
| Total | 2⁄3. |
Problem 18
Multiply 1⁄6 by 12⁄31⁄3.
| 1 | 1⁄6 | |
| 2⁄3 | 1⁄9 | |
| 1⁄3 | 1⁄18 | |
| Total | 1⁄3. |
Problem 19
Multiply 1⁄12 by 12⁄31⁄3.
| 1 | 1⁄12 | as | a | part | of | 18 | this | is | 11⁄2 | ||
| 2⁄3 | 1⁄18 | " | " | " | " | " | " | " | 1 | ||
| 1⁄3 | 1⁄36 | " | " | " | " | " | " | " | 1⁄2 | ||
| Total | 1⁄6 | since | " | " | " | " | " | " | " | 3. |
Problem 20
Multiply 1⁄24. by 12⁄31⁄3
| 1 | 1⁄24 | as | a | part | of | 18 | this | is | 1⁄21⁄4 | ||
| 2⁄3 | 1⁄36 | " | " | " | " | " | " | " | 1⁄2 | ||
| 1⁄3 | 1⁄72 | " | " | " | " | " | " | " | 1⁄4 | ||
| Total | 1⁄12 | since | " | " | " | " | " | " | " | 11⁄2. |
SECTION IV
Problems 21-23. Problems in Completion
Problem 21
It is said to thee, Complete 2⁄31⁄15 to 1.
Applied to 15, 2⁄3 is 10 and 1⁄15 is 1, making 11; the remainder is 4. Multiply 15 so as to get 4.
| 1 | 15 | |
| 1⁄10 | 11⁄2 | |
| \ | 1⁄5 | 3 |
| \ | 1⁄15 | 1 |
| Total | 4. | |
