Page:The Rhind Mathematical Papyrus, Volume I.pdf/85

From Wikisource
Jump to navigation Jump to search
This page has been proofread, but needs to be validated.
28]
SECTION V—QUANTITY PROBLEMS
69

Multiply 3 by 4.

  1 3
  2 6
\ 4 12;
The quantity is 12
  14 3
  Total 15.

Problem 27
A quantity and its 15, added together become 21. What is the quantity?

Assume 5.

\ 1 5
\ 15 1
Total|6.

As many times as 6 must be multiplied to give 21, so many times 5 must be multiplied to give the required number.

\ 1 6
\ 2 12
\ 12 3
Total 312
\ 1 312
  2 7
\ 4 14.
The quantity is 1712
  15 312
  Total 21.

Problem 28
A quantity and its 35 are added together and from the sum 13 of the sum is subtracted, and 10 remains. What is the quantity?

Subtract from 10 its 110, which is 1. The remainder is 9. This is the quantity; its 23, 6, added to 9, makes 15, and 13 of 15, taken away from 15, leaves 10. Do it thus . . . .