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TIMBER AND TIMBER TREES.
[CHAP.
Number of the specimen. |
Deflections. | Total weight required to break each piece. |
Specfic gravity. | Weight required to sepcific gravity 600. |
Weight required to break 1 square inch. |
Tensile Experiments | ||||
With the apparatus weighing 390 lbs. |
After the weight was removed. |
At the crisis of breaking |
Direct cohesion on 1 square in. |
Number of the specimen. | ||||||
Inches. | Inch. | Inches. | lbs. | lbs. | lbs. | |||||
35 | c′ | 1.500 | .150 | 4.000 | 760.00 | 550 | 829 | 190.00 | — | — |
36 | b′ | 1.400 | .150 | 3.750 | 710.00 | 580 | 734 | 177.50 | — | — |
37 | a′ | 1.500 | .200 | 4.000 | 705.00 | 560 | 755 | 176.25 | — | — |
38 | a | 1.250 | .000 | 3.750 | 765.00 | 595 | 771 | 191.25 | 3325 | 47 |
39 | b | 1.25 0 | .150 | 3.000 | 640.00 | 580 | 662 | 160.00 | 3080 | 48 |
40 | c | 1.350 | .100 | 5.250 | 810.00 | 555 | 876 | 202.50 | 3920 | 49 |
Total | 8.250 | .750 | 23.750 | 4390.00 | 3420 | 4627 | 1097.50 | — | — | |
Aver. | 1.375 | .125 | 3.958 | 731.66 | 570 | 771 | 182.91 | — | — |
Remarks.—These specimens broke with a moderate length of fracture.
E = 722360. S = 1922.
The mean of the whole being E = 698240. S = 1805.
Relatively considered, these experiments stand as follows:—
TRANVERSE STRENGTH | TENSILE STRENGTH |
Top-length | Top-length |
a – a′ = 0.87 | a – a′ = 1.00 |
b – b′ = 0.95 | b – b′ = 0.94 |
c – c′ = 1.00 | c – c′ = 0.73 |
Mid-length | Mid-length |
a – a′ = 1.00 | a – a′ = 1.00 |
b – b′ = 0.95 | b – b′ = 0.93 |
c – c′ = 0.95 | c – c′ = 0.93 |
Butt-length | Butt-length |
a – a′ = 0.94 | a – a′ = 0.85 |
b – b′ = 0.86 | b – b′ = 0.79 |
c – c′ = 1.00 | c – c′ = 1.00 |